Unit 1 Rigid Transformations And Congruence — Unit Plan

TitleTakeawaysVisual / Anchor ChartAssessment
Lesson 1
Moving in the Plane
Frame to Frame (1 problem)

Here are positions of a shape:

4 panels showing the same figure in different positions and orientations.

Describe how the shape moves from:

  1. Frame 1 to Frame 2.

  2. Frame 2 to Frame 3.

  3. Frame 3 to Frame 4.

Show Solution
  1. Slide down
  2. Turn counterclockwise 90 degrees (or one quarter of a full turn)
  3. Slide up
Lesson 2
Naming the Moves
Is It a Reflection? (1 problem)

What type of move takes Figure A to Figure B?

Two identical 4 sided figures labeled A and B share a common vertex. A dashed line labeled l slants downward and to the right and passes through the common vertex.

Explain your reasoning.

Show Solution

Sample responses:

  • The move is 1 rotation. If Figure A is turned around the point shared by Figures A and B, it can land on Figure B.
  • The move is 2 reflections. If Figure A is flipped over line \ell and then flipped over again so that the shared points and angle line up, then it can land on Figure B.
Lesson 3
Grid Moves
Triangle Images (1 problem)

  1. Translate triangle ABCABC so that BB goes to BB’.

  2. Reflect triangle ABCABC over line \ell.

Show Solution
Lesson 4
Making the Moves
What Does It Take? (1 problem)

Triangle A B C on a grid. Let (0 comma 0) be the bottom left corner. Then the coordinates of triangle A B C are A(7 comma 10), B(11 comma 9) and C(2 comma 3).

For each description of a transformation, identify what information is missing.

  1. Translate triangle ABCABC to the right.

  2. Rotate triangle ABCABC 9090^\circ around point CC.

  3. Reflect triangle ABCABC over a line.
     

Show Solution

Sample responses:

  1. Distancehow many units to the right
  2. Directionclockwise or counterclockwise
  3. A drawing or description of where the line is
Lesson 5
Coordinate Moves
Rotation or Reflection (1 problem)

One of the triangles pictured is a rotation of triangle ABCABC and one of them is a reflection.

<p>Triangle A B C reflected on a coordinate plane, origin O.</p>
Triangle A B C reflected on a coordinate plane, origin O. Horizontal axis scale negative 6 to 6 by 1’s. Vertical axis scale negative 5 to 5 by 1’s. Triangle A B C is blue and has coordinates: A(1 comma 1), B(3 comma 2) and C(2 comma 5). The green triangle has coordinates: (negative 1 comma 1), (negative 2 comma 3) and (negative 5 comma 2). The red triangle has coordinates: (1 comma negative 1), (3 comma negative 2) and (2 comma negative 5).

  1. Label the rotated image PQRPQR.
  2. Label the reflected image XYZXYZ.
Show Solution

<p>Image of sequence of transformations.</p>

Lesson 6
Describing Transformations
Describing a Sequence of Transformations (1 problem)

Triangle T' is the image of Triangle T. Han gave this information to Jada to describe the sequence of transformations. 

  • Triangle T is reflected over line \ell.
  • Triangle T is translated 2 units to the left.
  • The order of the sequence of transformations is translation, then reflection.

Which of these figures shows the correct Triangle T'? 

Figure 1

Figure 2

Show Solution

Figure 2

Section A Check
Section A Checkpoint
Problem 1

Here is line segment ABAB and a point CC

  1. Reflect line segment ABAB across the xx-axis. What are the coordinates of the new endpoints?
  2. Point CC is translated 3 units to the left and 2 units up. Plot this point on the grid and label it CC’.
Show Solution
  1. The image of AA is at (-4,-5)(\text-4,\text-5) and the image of BB is at (3,-2)(3, \text-2).
Problem 2

Here are 2 figures. Describe a sequence of transformations that takes triangle ABCABC to triangle DEFDEF.

Show Solution
Sample response: Translate triangle ABCABC so that AA moves to DD. Rotate 90 degrees counterclockwise around point DD.
 
Lesson 7
No Bending or Stretching
Translated Trapezoid (1 problem)

Trapezoid ABCDA’B’C’D’ is the image of trapezoid ABCDABCD under a rigid transformation.

Trapezoid A B C D and its image, trapezoid A prime B prime C prime and D prime.<br>
 
Trapezoid A B C D and its image, trapezoid A prime B prime C prime and D prime. Angle A is 130 degrees, angle B is 50 degrees and angles D and C are right angles. Side A prime D prime is 6 units and side D prime C prime is 4 units.  

  1. Label all vertices on trapezoid ABCDA’B’C’D’.
  2. On both figures, label all known side lengths and angle measures.
Show Solution

<p>Transformations on quadrilateral ABCD.</p>

Lesson 8
Rotation Patterns
Is It a Rotation? (1 problem)

Triangle ABCABC is rotated 180180^\circ around point CC. Will the image line up with triangle CDECDE? Explain how you know.

Two identical triangles labeled A and B that share a common vertex. A dashed line labeled l slants downward and to the right and passes through the common vertex.

Show Solution

No. Sample response: If triangle CDECDE was a 180180^\circ rotation of triangle ABCABC, then line segment ABAB would be parallel to line segment DEDE.

Lesson 9
Moves in Parallel
Finding Unknown Measurements (1 problem)

Points AA’ and BB’ are the images of AA and BB after a 180180^\circ rotation around point OO.

Lines A A prime and B B prime intersect at point O. Angle A O B is 79 degrees.

Answer each question and explain your reasoning without measuring segments or angles.

  1. Name a segment whose length is the same as segment AOAO.
  2. What is the measure of angle AOBA'OB'?
Show Solution
  1. Segment AOA’O, because AA’ is the image of AA after a 180180^\circrotation with center at OO. This rotation preserves distances and takes segment AOAO to segment AOA’O.
  2. 7979^\circ, the same measure as AOB\angle AOB, because the 180180^\circ rotation with center at OO takes AOB\angle AOB to AOB\angle A’OB’. The rotation preserves angle measures.
Lesson 10
Composing Figures
Identifying Side Lengths and Angle Measures (1 problem)

Two quadrilaterals, A B C D on the left and A B C E.<br>
 
Two quadrilaterals, A B C D on the left and A B C E on the right. Both have segment A C, and quadrilateral A B C E has midpoint M on A C. Quadrilateral A B C D has side A B length 2 point 7, angle B is 64 point 3 degrees and side B C is 3 point 2. Quadrilateral has  A B C E has side A B length 2 point 7, angle B is 64 point 3 degrees and side B C is 3 point 2. Point E on quadrilateral A B C E is about the same level as the midpoint M and angle B. Point D on quadrilateral A B C D is above the level of the angle B and the midpoint of segment A C.  

Here is a diagram showing triangle ABCABC and some transformations of triangle ABCABC.

On the left side of the diagram, triangle ABCABC has been reflected across line ACAC to form quadrilateral ABCDABCD. On the right side of the diagram, triangle ABCABC has been rotated 180180^\circusing midpoint MM as a center to form quadrilateral ABCEABCE.

Using what you know about rigid transformations, side lengths and angle measures, label as many side lengths and angle measures as you can in quadrilaterals ABCDABCD and ABCEABCE.

Show Solution

<p>Transformation of triangle ABC.</p>

Section B Check
Section B Checkpoint
Problem 1

Here is a line segment CDCD with midpoint MM.

  1. Rotate segment CDCD 9090^\circ clockwise around point MM, and label the image as FGFG.
  2. Rotate segment CDCD 180180^\circ around point EE and label the new segment HJHJ
  3. Which segment is parallel to segment CDCD?
Show Solution

  1. See image
  2. See image
  3. HJHJ is parallel to CDCD
Problem 2

Triangle EDCEDC is the image of triangle ABCABC after a rigid transformation.

  1. Describe a rigid transformation that takes ABCABC to EDCEDC.
  2. Name 2 angles that have the same measure and explain how you know.
  3. Name 2 side lengths that must be the same and explain how you know.
Show Solution

Sample responses:

  1. Rotate triangle ABCABC 180180^\circ around point CC.
  2. Angle AA is the same as angle EE, or angle BB is the same as angle DD, or angle ACBACB is the same as angle ECDECD; since triangle EDCEDC is the image of triangle ABCABC after a rigid transformation, the corresponding angles are the same measure.
  3. ABAB is the same length as EDED, or BCBC is the same length as DCDC, or ACAC is the same length as ECEC; since triangle EDCEDC is the image of triangle ABCABC after a rigid transformation, the corresponding side lengths are the same.
Lesson 11
What Is the Same?
Mirror Images (1 problem)

Figure B is the image of Figure A when reflected across line \ell. Are Figure A and Figure B congruent? Explain your reasoning.

Figures A and B and line l. Figure B is a reflection of figure A over the vertical line l.

Show Solution

Yes, they are congruent. There is a rigid transformation that takes one figure to the other, so they are congruent.

Lesson 12
Congruent Polygons
Moving to Congruence (1 problem)

Describe a sequence of reflections, rotations, and translations that shows that quadrilateral ABCDABCD is congruent to quadrilateral EFGHEFGH.

Two figures, trapezoids A B C D and E F G H on a square grid.
Two figures, trapezoids A B C D and E F G H on a square grid. Let the lower left corner be (0 comma 0), Then trapezoid A B C D has points A(1 comma 6), B(1 comma 2), C(6 comma 2) and D(2 comma 6). Trapezoid E F G H has points E(7 comma 6), F(11 comma 6), G(11 comma 1) and H(7 comma 6).

Show Solution

Sample response: Translate ABCDABCD down 1 and 5 to the right. Then reflect over line GHGH.

Lesson 13
Congruence
Explaining Congruence (1 problem)

Are Figures A and B congruent? Explain your reasoning.

Two ovals, figure A and figure B on a square grid. Figure A is 2 units tall and 3 units wide. Figure B is 2 units tall and 4 units wide.

Show Solution

These figures are not congruent. Sample reasoning: If they were congruent, the longest horizontal distances between two points would be the same. However, for A it is less than 4 units, and for B it is about 4 units.

Section C Check
Section C Checkpoint
Problem 1

  1. Which shape is congruent to Shape A? Describe a rigid transformation that takes A to that figure.
  2. Which shape is not congruent to Shape A? Explain how you know.
Show Solution
  1. Shape B is congruent to Shape A. Sample response: Translate Shape A 4 units right, then rotate 9090^\circ clockwise around (2,1)(2, 1).
  2. Shape C is not congruent to Shape A. Sample response: Shape C has 2 side lengths of 3, but Shape A has no side lengths of 3, so they cannot be congruent.
Lesson 14
Alternate Interior Angles
All the Rest (1 problem)

The diagram shows two parallel lines cut by a transversal. One angle measure is shown.

Two lines that do not intersect. A third line intersects with both lines.
Two lines that do not intersect. A third line intersects with both lines. At the first intersection, angles are marked in clockwise order as a degrees, b, degrees, c degrees, and 54 degrees. At the second intersection, angles are marked in clockwise order as e degrees, f degrees, g degrees, and d degrees.

Find the values of aa, bb, cc, dd, ee, ff, and gg.

Show Solution

aa: 126126bb: 5454, cc: 126126, dd: 5454, ee: 126126, ff: 5454, gg: 126126

Lesson 15
Adding the Angles in a Triangle
Three Angles (1 problem)

Tyler has 3 right angles. Can he use them to make a triangle? Explain your reasoning.

Show Solution

No. Sample reasoning: 3 right angles sums to more than 180 degrees, since 390=2703\boldcdot90=270.

Lesson 16
Parallel Lines and the Angles in a Triangle
Angle Sum (1 problem)

What is the sum of the angle measures of triangle ABCABC? How do you know?

Show Solution
180180^\circ. Sample response: Since the base and vertex lie on grid lines, we can see the line parallel to BCBC through AA is a straight line. The three angles around point AA add up to a straight angle. Using alternate interior angles, two angles are congruent to angle BB and angle CC, and the third angle is the same as angle AA. So angles AA, BB, and CC add up to 180180^\circ.
Section D Check
Section D Checkpoint
Problem 1

Line FGFG is parallel to line HJHJ and cut by transversal mm. Find each angle measure:

  1. aa
  2. bb
  3. cc
  4. dd
Show Solution
  1. 4545^\circ
  2. 135135^\circ
  3. 4545^\circ
  4. 135135^\circ
Problem 2

Line ABAB is parallel to line CDCD. Explain how you know that the sum of the angles of triangle ABCABC is 180180^\circ.

Show Solution
Sample response: Angles ECAECA, ACBACB, and BCDBCD form a straight angle, which is 180180^\circ. Angle ECAECA is congruent to angle CABCAB because they are alternate interior angles. Angle BCDBCD is congruent to angle CBACBA because they are alternate interior angles. So the angles in triangle ABCABC are congruent to the angles that make a straight angle and must also sum to 180180^\circ.
Lesson 17
Rotate and Tessellate
No cool-down
Unit 1 Assessment
End-of-Unit Assessment