Algebra I

End-of-Unit Assessment

January 2026 Released Items
1.

A parabola is graphed on the set of axes below.

Image Description: A coordinate plane with a parabola that opens upward with vertex at (3, -4). The parabola passes through approximately (1, 0) and (5, 0).

What are the equation of the axis of symmetry and the coordinates of the vertex of this parabola?

(1) x=3x = 3 and (3,4)(3, -4)
(2) y=3y = 3 and (3,4)(3, -4)
(3) x=4x = -4 and (4,3)(-4, 3)
(4) y=4y = -4 and (4,3)(-4, 3)

Original screenshot of question 1
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2.

The product of 25\sqrt{25} and 2\sqrt{2} will result in

(1) an irrational number
(2) a rational number
(3) a natural number
(4) an integer

Original screenshot of question 2
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3.

When f(x)=4x+2f(x) = |4x + 2| and g(x)=3x+5g(x) = 3x + 5 are graphed on the same set of axes, for which value of xx is f(x)=g(x)f(x) = g(x)?

(1) 1
(2) 2
(3) 3
(4) 14

Original screenshot of question 3
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4.

The expression x226x120x^2 - 26x - 120 is equivalent to

(1) (x+4)(x30)(x + 4)(x - 30)
(2) (x4)(x+30)(x - 4)(x + 30)
(3) (x20)(x+6)(x - 20)(x + 6)
(4) (x+20)(x6)(x + 20)(x - 6)

Original screenshot of question 4
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Algebra
5.

The expression 325+653 - 2\sqrt{5} + 6\sqrt{5} is equivalent to

(1) 757\sqrt{5}
(2) 7107\sqrt{10}
(3) 3+453 + 4\sqrt{5}
(4) 3+4103 + 4\sqrt{10}

Original screenshot of question 5
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6.

Students were asked to write a polynomial given the following conditions:

  • the degree of the expression is 3
  • the leading coefficient is 2
  • the constant term is 6-6

Which expression satisfies all three conditions?

(1) 4x6+3x24x - 6 + 3x^2
(2) 3x26x+43x^2 - 6x + 4
(3) 46x+2x34 - 6x + 2x^3
(4) 4x2+2x364x^2 + 2x^3 - 6

Original screenshot of question 6
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Algebra
7.

Which graph below represents a function?

Image Description: Four graphs on coordinate planes.

Graph (1): Five points plotted at (1,1)(1, 1), (2,2)(2, 2), (3,2)(3, 2), (4,4)(4, 4), and (5,4)(5, 4).

Graph (3): Six points plotted at (1,1)(1, 1), (2,2)(2, 2), (2,3)(2, 3), (2,4)(2, 4), (2,5)(2, 5), and (5,4)(5, 4).

Graph (2): A step function with horizontal segments. An open circle at (1,1)(1, 1) with a horizontal line to a closed circle at (3,1)(3, 1). An open circle at (3,3)(3, 3) with a horizontal line to a closed circle at (4,3)(4, 3). A closed circle at (4,5)(4, 5) with a horizontal line to a closed circle at (5,5)(5, 5).

Graph (4): A step function with vertical segments. A closed circle at (1,1)(1, 1) with a vertical line to a closed circle at (1,3)(1, 3). A horizontal line to a closed circle at (3,3)(3, 3), then a vertical line up to a closed circle at (3,4)(3, 4). A horizontal line to an open circle at (5,4)(5, 4), then a vertical line up to an open circle at (5,5)(5, 5).

(1) Graph 1
(2) Graph 2
(3) Graph 3
(4) Graph 4

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8.

The following function models the value of a diamond ring, in dollars, tt years after it is purchased:

v(t)=500(1.08)tv(t) = 500(1.08)^t

What was the original price of the ring, in dollars?

(1) $108
(2) $460
(3) $500
(4) $540

Original screenshot of question 8
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9.

The formula for the surface area of a cylinder can be expressed as S=2πr2+2πrhS = 2\pi r^2 + 2\pi rh, where rr is the radius and hh is the height of the cylinder. What is the height, hh, expressed in terms of SS, π\pi, and rr?

(1) h=S2πr22πrh = \frac{S - 2\pi r^2}{2\pi r}
(2) h=Srh = S - r
(3) h=2πr2S2πrh = \frac{2\pi r^2 - S}{2\pi r}
(4) h=rSh = r - S

Original screenshot of question 9
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Algebra
10.

When solving the following system of equations algebraically, Mason used the substitution method.

3xy=103x - y = 10

2x+5y=12x + 5y = 1

Which equation could he have used?

(1) 2(3x10)+5x=12(3x - 10) + 5x = 1
(2) 2(3x+10)+5x=12(-3x + 10) + 5x = 1
(3) 2x+5(3x10)=12x + 5(3x - 10) = 1
(4) 2x+5(3x+10)=12x + 5(-3x + 10) = 1

Original screenshot of question 10
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11.

Which graph represents the solution to the inequality 4+3x>97x4 + 3x > 9 - 7x?

Image Description: Four number lines from 0 to 3 with tick marks at every 12\frac{1}{2}.

Graph (1): Open circle at 22, arrow pointing left.

Graph (2): Open circle at 22, arrow pointing right.

Graph (3): Open circle at 12\frac{1}{2}, arrow pointing right.

Graph (4): Open circle at 12\frac{1}{2}, arrow pointing left.

(1) Graph 1
(2) Graph 2
(3) Graph 3
(4) Graph 4

Original screenshot of question 11
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12.

When solving the equation 3(2x+5)8=7x+103(2x + 5) - 8 = 7x + 10, the first step could be 3(2x+5)=7x+183(2x + 5) = 7x + 18. Which property justifies this step?

(1) addition property of equality
(2) commutative property of addition
(3) multiplication property of equality
(4) distributive property of multiplication over addition

Original screenshot of question 12
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13.

Which table of values best models an exponential decay function?

  1. xxf(x)f(x)
    2-277
    1-144
    0011
    112-2
    225-5
    338-8
  2. mmf(m)f(m)
    00200200
    11180180
    22162162
    33146146
    44131131
    55118118
  3. nnf(n)f(n)
    00200200
    11210210
    22220220
    33231231
    44242242
    55254254
  4. ppf(p)f(p)
    3-32-2
    2-25-5
    1-15-5
    005-5
    1133
    2233
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14.

If f(x)=x+1+5f(x) = \sqrt{x + 1} + 5, then what is the value of f(3)f(3)?

(1) 9
(2) 7
(3) 3
(4) 10

Original screenshot of question 14
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15.

Isabella wants to shift the graph of the function f(x)=(x+5)22f(x) = (x + 5)^2 - 2 left 3 units. Which function represents the shifted graph?

(1) g(x)=(x+2)22g(x) = (x + 2)^2 - 2
(2) g(x)=(x+8)22g(x) = (x + 8)^2 - 2
(3) g(x)=(x+5)25g(x) = (x + 5)^2 - 5
(4) g(x)=(x+5)2+1g(x) = (x + 5)^2 + 1

Original screenshot of question 15
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16.

What are the zeros of f(x)=x(x236)f(x) = x(x^2 - 36)?

(1) 0, only
(2) 6, only
(3) 6 and 6-6, only
(4) 0, 6, and 6-6

Original screenshot of question 16
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17.

The point (x,6)(x, -6) lies on the graph of a parabola whose equation is y=x2x+6y = -x^2 - x + 6. The value of xx can be

(1) 3-3 or 22
(2) 4-4 or 33
(3) 3, only
(4) 4-4, only

Original screenshot of question 17
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18.

The two-way frequency table below is a summary of concession stand sales for a football game.

SodaWaterCoffeeTotal
Hot Dogs506246158
Pizza120584182
No Food30201060
Total20014060400

Of the people making a purchase at the concession stand, what is the relative frequency of them buying pizza and a water?

(1) 0.58
(2) 0.35
(3) 0.455
(4) 0.145

Original screenshot of question 18
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19.

When Theodore was driving in Canada, his speed was 104 kilometers per hour. Theodore was asked to convert his metric speed to a different rate, using the following conversion:

104 km1 hr×1 hr60 min×1 min60 sec×0.6214 mi1 km×5280 ft1 mi\frac{104 \text{ km}}{1 \text{ hr}} \times \frac{1 \text{ hr}}{60 \text{ min}} \times \frac{1 \text{ min}}{60 \text{ sec}} \times \frac{0.6214 \text{ mi}}{1 \text{ km}} \times \frac{5280 \text{ ft}}{1 \text{ mi}}

Assuming he did all the work correctly, what would be the units for Theodore's rate?

(1) feet per second
(2) feet per minute
(3) seconds per foot
(4) minutes per foot

Original screenshot of question 19
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20.

Which expression is equivalent to (2x2)3(-2x^2)^3?

(1) 2x5-2x^5
(2) 2x6-2x^6
(3) 8x5-8x^5
(4) 8x6-8x^6

Original screenshot of question 20
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21.

The table below shows the amount of a radioactive substance that remained for selected years.

Year2000200120052010201420172019
Amount Remaining (grams)7504502198525128

To the nearest tenth, the average rate of change, in grams per year, from 2000 to 2014 is

(1) 39.1
(2) 51.8
(3) 39.1-39.1
(4) 51.8-51.8

Original screenshot of question 21
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22.

When 2x23x+42x^2 - 3x + 4 is subtracted from x2+2x5x^2 + 2x - 5, the result is

(1) x25x+9x^2 - 5x + 9
(2) x2x+1x^2 - x + 1
(3) x2+5x9-x^2 + 5x - 9
(4) x2x1-x^2 - x - 1

Original screenshot of question 22
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23.

Which equation has the same solution as x26x=24x^2 - 6x = 24?

(1) (x3)2=24(x - 3)^2 = 24
(2) (x6)2=24(x - 6)^2 = 24
(3) (x3)2=33(x - 3)^2 = 33
(4) (x6)2=60(x - 6)^2 = 60

Original screenshot of question 23
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24.

In a sequence, the first term is 2-2 and the common ratio is 3-3. The fourth term in this sequence is

(1) 162-162
(2) 11-11
(3) 24
(4) 54

Original screenshot of question 24
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25.

Solve the equation for xx:

14x=3(1+2x)4x14x = 3(1 + 2x) - 4x

Original screenshot of question 25
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26.

Graph f(x)=3(2)xf(x) = 3(2)^x over the interval 1x2-1 \leq x \leq 2.

Image Description: A coordinate grid is provided with the horizontal axis labeled xx and the vertical axis labeled f(x)f(x). The grid has gridlines for plotting points.

Original screenshot of question 26
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27.

Determine the product of (2x+3)(2x + 3) and (6x2+5x1)(-6x^2 + 5x - 1).

Express the product in standard form.

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28.

A student's test scores for the semester are listed below.

83, 87, 90, 94, 94, 93, 95, 70, 72, 83, 85, 88, 98

Construct a box plot for this data set, using the number line below.

Image Description: A number line labeled "Student Test Scores" is provided, ranging from 70 to 100 with tick marks at every 2 units.

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29.

Write an equation, in slope-intercept form, of a line that passes through the point (6,3)(6, 3) and has a slope of 23\frac{2}{3}.

Original screenshot of question 29
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30.

Abby has $20 to spend at a community festival. She uses $8.50 to purchase food coupons for popcorn, a hot dog, and a soda.

She can buy individual ride tickets for $2.25 each. Determine algebraically the maximum number of ride tickets Abby can buy.

Original screenshot of question 30
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31.

A rocket was launched from the ground into the air at an initial velocity of 80 feet per second. The path of the rocket can be modeled by h(t)=16t2+80th(t) = -16t^2 + 80t, where tt represents the time after the rocket has been launched, and h(t)h(t) represents the height of the rocket.

Image Description: A coordinate grid is provided with the horizontal axis labeled "Time (in seconds)" ranging from 0 to 6, and the vertical axis labeled "Height (in feet)" ranging from 0 to 100, with gridlines at intervals of 10 on the vertical axis and 1 on the horizontal axis.

Original screenshot of question 31
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32.

Use the quadratic formula to solve 2x24x3=02x^2 - 4x - 3 = 0, and express the answer in simplest radical form.

Original screenshot of question 32
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33.

The table below shows the ages of drivers and the annual cost of their car insurance.

Age (xx) (in years)16171818212230
Annual Cost of Car Insurance (yy) (in dollars)145213321284132012001188600
Original screenshot of question 33
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34.

Solve the following system of inequalities graphically.

2yx+62y \leq x + 6

2x+y>32x + y > 3

Label the solution set SS.

Image Description: A coordinate grid is provided with the horizontal axis labeled xx and the vertical axis labeled yy, with gridlines for plotting.

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35.

Acme Athletics purchases shoes from a supply company. In January the store bought 30 pairs of running shoes and 10 pairs of basketball shoes for $3700. In March they bought 15 pairs of running shoes and 20 pairs of basketball shoes for $3575. The supply company kept their prices constant.

If xx represents the cost of one pair of running shoes and yy represents the cost of one pair of basketball shoes, write a system of equations that models this situation.

Original screenshot of question 35
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Algebra

Answer Key

1.

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2.

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3.

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4.

(1)

5.

(3)

6.

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7.

(1)

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10.

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11.

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12.

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13.

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14.

(2)

15.

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16.

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17.

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20.

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25.

x=312=14x = \frac{3}{12} = \frac{1}{4}

Solution:

Distribute the 3 on the right side:

14x=3+6x4x14x = 3 + 6x - 4x

Combine like terms on the right side:

14x=3+2x14x = 3 + 2x

Subtract 2x2x from both sides:

12x=312x = 3

Divide both sides by 12:

x=312=14x = \frac{3}{12} = \frac{1}{4}

26.

An exponential curve passing through (1,1.5)(-1, 1.5), (0,3)(0, 3), (1,6)(1, 6), and (2,12)(2, 12).

Solution:

Create a table of values for f(x)=3(2)xf(x) = 3(2)^x over the interval 1x2-1 \leq x \leq 2:

When x=1x = -1: f(1)=3(2)1=312=1.5f(-1) = 3(2)^{-1} = 3 \cdot \frac{1}{2} = 1.5

When x=0x = 0: f(0)=3(2)0=31=3f(0) = 3(2)^0 = 3 \cdot 1 = 3

When x=1x = 1: f(1)=3(2)1=32=6f(1) = 3(2)^1 = 3 \cdot 2 = 6

When x=2x = 2: f(2)=3(2)2=34=12f(2) = 3(2)^2 = 3 \cdot 4 = 12

Plot the points (1,1.5)(-1, 1.5), (0,3)(0, 3), (1,6)(1, 6), and (2,12)(2, 12) on the grid and connect them with a smooth exponential curve.

27.

12x38x2+13x3-12x^3 - 8x^2 + 13x - 3

Solution:

Multiply each term of (2x+3)(2x + 3) by each term of (6x2+5x1)(-6x^2 + 5x - 1):

2x(6x2)+2x(5x)+2x(1)+3(6x2)+3(5x)+3(1)2x(-6x^2) + 2x(5x) + 2x(-1) + 3(-6x^2) + 3(5x) + 3(-1)

=12x3+10x22x18x2+15x3= -12x^3 + 10x^2 - 2x - 18x^2 + 15x - 3

Combine like terms:

=12x3+(10x218x2)+(2x+15x)3= -12x^3 + (10x^2 - 18x^2) + (-2x + 15x) - 3

=12x38x2+13x3= -12x^3 - 8x^2 + 13x - 3

28.

Box plot with minimum = 70, Q1Q_1 = 83, median = 88, Q3Q_3 = 94, maximum = 98.

Solution:

First, arrange the data in order from least to greatest:

70, 72, 83, 83, 85, 87, 88, 90, 93, 94, 94, 95, 98

There are 13 data values.

Minimum: 70

Maximum: 98

Median (Q2): The middle value is the 7th value: 88

Q1: The median of the lower half (70, 72, 83, 83, 85, 87) is 83+832=83\frac{83 + 83}{2} = 83

Q3: The median of the upper half (90, 93, 94, 94, 95, 98) is 94+942=94\frac{94 + 94}{2} = 94

Draw the box plot on the number line with a whisker from 70 to 83, a box from 83 to 94 with a line at 88 for the median, and a whisker from 94 to 98.

29.

y=23x1y = \frac{2}{3}x - 1

Solution:

Use the slope-intercept form y=mx+by = mx + b, where m=23m = \frac{2}{3}.

Substitute the point (6,3)(6, 3) and the slope into the equation to find bb:

3=23(6)+b3 = \frac{2}{3}(6) + b

3=4+b3 = 4 + b

b=1b = -1

The equation is y=23x1y = \frac{2}{3}x - 1.

30.

5 ride tickets

Solution:

Abby starts with $20 and spends $8.50 on food, so she has:

208.50=11.5020 - 8.50 = 11.50

Each ride ticket costs $2.25. Let tt represent the number of ride tickets. Set up the inequality:

2.25t11.502.25t \leq 11.50

Divide both sides by 2.25:

t11.502.25t \leq \frac{11.50}{2.25}

t5.1t \leq 5.\overline{1}

Since Abby can only buy whole tickets, the maximum number of ride tickets she can buy is 5.

31.

A downward-opening parabola passing through (0,0)(0, 0), (1,64)(1, 64), (2,96)(2, 96), (2.5,100)(2.5, 100), (3,96)(3, 96), (4,64)(4, 64), and (5,0)(5, 0).

Solution:

Create a table of values for h(t)=16t2+80th(t) = -16t^2 + 80t:

h(0)=16(0)2+80(0)=0h(0) = -16(0)^2 + 80(0) = 0

h(1)=16(1)2+80(1)=16+80=64h(1) = -16(1)^2 + 80(1) = -16 + 80 = 64

h(2)=16(4)+80(2)=64+160=96h(2) = -16(4) + 80(2) = -64 + 160 = 96

h(2.5)=16(6.25)+80(2.5)=100+200=100h(2.5) = -16(6.25) + 80(2.5) = -100 + 200 = 100

h(3)=16(9)+80(3)=144+240=96h(3) = -16(9) + 80(3) = -144 + 240 = 96

h(4)=16(16)+80(4)=256+320=64h(4) = -16(16) + 80(4) = -256 + 320 = 64

h(5)=16(25)+80(5)=400+400=0h(5) = -16(25) + 80(5) = -400 + 400 = 0

Plot these points and connect them with a smooth parabolic curve opening downward.

32.

x=2±102x = \frac{2 \pm \sqrt{10}}{2}

Solution:

Identify a=2a = 2, b=4b = -4, c=3c = -3.

Apply the quadratic formula x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}:

x=(4)±(4)24(2)(3)2(2)x = \frac{-(-4) \pm \sqrt{(-4)^2 - 4(2)(-3)}}{2(2)}

x=4±16+244x = \frac{4 \pm \sqrt{16 + 24}}{4}

x=4±404x = \frac{4 \pm \sqrt{40}}{4}

Simplify 40=410=210\sqrt{40} = \sqrt{4 \cdot 10} = 2\sqrt{10}:

x=4±2104x = \frac{4 \pm 2\sqrt{10}}{4}

Simplify by dividing numerator and denominator by 2:

x=2±102x = \frac{2 \pm \sqrt{10}}{2}

33.

y=56.97x+2352.22y = -56.97x + 2352.22

Solution:

Using a graphing calculator or statistical software, enter the data points:

(16,1452),(17,1332),(18,1284),(18,1320),(21,1200),(22,1188),(30,600)(16, 1452), (17, 1332), (18, 1284), (18, 1320), (21, 1200), (22, 1188), (30, 600)

Perform a linear regression (LinReg) to find the equation of the line of best fit.

The linear regression equation, rounded to the nearest hundredth, is:

y=56.97x+2352.22y = -56.97x + 2352.22

34.

The solution set SS is the overlapping region below (and on) the line y=12x+3y = \frac{1}{2}x + 3 and above (but not on) the line y=2x+3y = -2x + 3.

Solution:

Rewrite each inequality in slope-intercept form:

First inequality: 2yx+62y \leq x + 6

y12x+3y \leq \frac{1}{2}x + 3

Graph y=12x+3y = \frac{1}{2}x + 3 as a solid line (since \leq) with a slope of 12\frac{1}{2} and yy-intercept of 3. Shade below the line.

Second inequality: 2x+y>32x + y > 3

y>2x+3y > -2x + 3

Graph y=2x+3y = -2x + 3 as a dashed line (since >>) with a slope of 2-2 and yy-intercept of 3. Shade above the line.

The solution set SS is the region where the two shadings overlap.

35.

30x+10y=370030x + 10y = 3700

15x+20y=357515x + 20y = 3575

Solution:

In January, 30 pairs of running shoes and 10 pairs of basketball shoes cost $3700:

30x+10y=370030x + 10y = 3700

In March, 15 pairs of running shoes and 20 pairs of basketball shoes cost $3575:

15x+20y=357515x + 20y = 3575