Writing and Graphing Systems of Linear Equations

Student Summary

A costume designer needs some silver and gold thread for the costumes for a school play. She needs a total of 240 yards. At a store that sells thread by the yard, silver thread costs $0.04 a yard and gold thread costs $0.07 a yard. The designer has $15 to spend on the thread.

How many of each color should she get if she is buying exactly what is needed and spending all of her budget?

This situation involves two quantities and two constraints—length and cost. Answering the question means finding a pair of values that meets both constraints simultaneously. To do so, we can write two equations and graph them on the same coordinate plane.

Let xx represents yards of silver thread and yy yards of gold thread. 

  • The length constraint: x+y=240x + y = 240
  • The cost constraint: 0.04x+0.07y=150.04x + 0.07y = 15

Every point on the graph of x+y=240x+y=240 is a pair of values that meets the length constraint.

Every point on the graph of 0.04x+0.07y=150.04x + 0.07y = 15 is a pair of values that meets the cost constraint.

The point where the two graphs intersect gives the pair of values that meets both constraints. 

<p>Graph. Yards of gold thread. Yards of silver thread.</p>
Graph of 2 intersecting lines, origin O. Horizontal axis 0 to 280, by 20’s, labeled, yards of silver thread. Vertical from 0 to 280, by 20’s, labeled yards of gold thread. Line 1 starts at 240 comma 0, passes through 60 comma 180, ends at 240 comma 0. Line 2 starts at 0 comma 214 point 2 9, passes through 60 comma 180, ends at 280 comma 54 point 2 9.  
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That point is (60,180)(60, 180), which represents 60 yards of silver thread and 180 yards of gold thread.

If we substitute 60 for xx and 180 for yy in each equation, we find that these values make the equation true. (60,180)(60,180) is a solution to both equations simultaneously. 

x+y=24060+180=240240=240\begin{aligned} x+y&=240\\ 60+180&=240\\ 240&=240 \end{aligned}

 0.04x+0.07y=150.04(60)+0.07(180)=152.40+12.60=1515=15\begin{aligned} 0.04x + 0.07y &= 15\\ 0.04(60) + 0.07(180) &=15\\ 2.40 + 12.60 &=15\\ 15&=15 \end{aligned}

Two or more equations that represent the constraints in the same situation form a system of equations. A curly bracket is often used to indicate a system.

{x+y=2400.04x+0.07y=15\begin {cases} x + y = 240\\0.04x + 0.07y = 15 \end {cases}

The solution to a system of equations is a pair of values that makes all of the equations in the system true. Graphing the equations is one way to find the solution to a system of equations.

Visual / Anchor Chart

Standards

Building On
8.EE.8.a

Analyze and solve pairs of simultaneous linear equations. Understand that solutions to a system of two linear equations in two variables correspond to points of intersection of their graphs. Solve systems of two linear equations in two variables with integer coefficients: graphically, numerically using a table, and algebraically. Solve real-world and mathematical problems involving systems of two linear equations in two variables with integer coefficients.

8.EE.8.b

Analyze and solve pairs of simultaneous linear equations. Understand that solutions to a system of two linear equations in two variables correspond to points of intersection of their graphs. Solve systems of two linear equations in two variables with integer coefficients: graphically, numerically using a table, and algebraically. Solve real-world and mathematical problems involving systems of two linear equations in two variables with integer coefficients.

Addressing
A-CED.36 questions

Represent constraints by equations or inequalities, and by systems of equations and/or inequalities, and interpret solutions as viable or non-viable options in a modeling context.

Q2 · 2ptJune 2024
Regents June 2024 Question 2
Q35 · 6ptJune 2024
Regents June 2024 Question 35
Q31 · 4ptJanuary 2025
Regents January 2025 Question 31
Q35 · 6ptAugust 2025
Regents August 2025 Question 35
Q35 · 6ptJanuary 2025
Regents January 2025 Question 35
Q35 · 6ptJune 2025
Regents June 2025 Question 35
A-REI.6

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A-REI.A

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Building Toward
A-REI.6

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